J.R. S. answered 04/13/21
Ph.D. University Professor with 10+ years Tutoring Experience
pOH = 14 - pH = 14 - 13.29 = 0.71
[OH-] = 0.195 M
Diluted 1 million times = 0.195 M / 106 = 1.95x10-7 M
Adding in the 1x10-7 M OH- from autoionization of H2O we would have...
1.95x10-7 + 1.0x10-7 = 2.95x10-7 M OH-
pOH = -log 2.95x10-7 = 6.53
pH = 14 - pOH
pH = 7.47