J.R. S. answered 04/13/21
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q = mC∆T
q = heat = 5000 J
m = mass = ?
C = specific heat = 0.385 J/gº
∆T = change in temp = 200 - 100 = 100º
solving for m (mass) we have...
m = q /(C)(∆T) = 5000 J /(0.385 J/gº)(100º)
m = 130. g