How many grams of magnesium would you need to replace all of the copper in 50 mL of a .5 M copper (ii) sulfate solution?

Question

show work / reasoning for the solution

Answer 1

50 ml x 1 L/1000 ml x 0.5 mol/L = 0.025 moles CuSO₄ = 0.025 mol Cu²⁺

To replace 0.025 moles Cu²⁺ with Mg²⁺, would require 0.025 moles Mg²⁺

grams of Mg needed = 0.025 mol Mg x 24.3 g / mol = 0.6 g Mg