Determine E° for the half-reaction In³⁺(aq) + 3 e⁻ → In(s).

Question

2In(s) + 6H+(aq) -> 2In^3+(aq) + 3H2(g)

E = +0.32 V

Answer 1

2In(s) + 6H⁺(aq) -> 2In³⁺(aq) + 3H₂(g)

n = 6 electrons

E_cell = Eº - RT/nF ln Q

@25ºC and converting to log base 10, we have...

E_cell = Eº -0.0592/n (log Q)

Under standard conditions, [In³⁺] and [H⁺] = 1 M so Q = 1 and log Q = 0

E_cell = Eº -0

Eº = E_cell = +0.32V