J.R. S. answered 04/13/21
Ph.D. University Professor with 10+ years Tutoring Experience
NO3- ==> NO ... unbalanced
NO3- ==> NO + 2H2O ... balanced for N and O
NO3- + 4H+ ==> NO + 2H2O ... balanced for N, O and H using acid
NO3- + 4H+ + 3e- ==> NO + 2H2O ... balanced for N, O, H and charge = balanced half reaction