J.R. S. answered 04/13/21
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = ?
m = mass = 15 g
C = specific heat = 0.129 J/gº
∆T = change in temperature = 85º - 22º = 63º
q = (15 g)(0.129 J/gº)(63º) = 122 J