a plane is traveling to Airport A and is 300 miles away when it is asked to divert to Airport B due to inclement. Airport B is 175 miles away from the plane and 200 miles away from airport A

Question

to the new tenth of a degree, at what angle must the plane turn to head towards Airport B?

Answer 1

It's a 300-175-200 triangle, use the law of cosines

200= 300^2 + 175^2 - 2(300)(175)cosP

cosP =0.7679

P = 39.84 degrees

other angles found the same way are A=34.09, B = 106.07

they sum to 180 degrees, as all triangles do.