What does 64t in the equation mean in terms of the rocket?

Question

A rocket is shot into the air. Its height, h, in feet as a function of the time, t in seconds that it has been in flight is given by the equation h (t) = -16t + 64t + 5. The graph is shown.

graph link: https://drive.google.com/file/d/1Q4_fY_tTmqYiToX9usaOed1njPPowua9/view?usp=drivesdk

What does 64t in the equation mean in terms of the rocket?

A. 64 feet is the maximum height of the rocket.

B. 64 seconds is how long it takes the rocket to reach its maximum height.

C. The initial speed of the rocket is 64 feet per second

D. 64t is a constant with no special meaning in the problem.

Answer 1

C) 64 is the initial speed of the rocket. initial velocity is the coefficient of the t term. 64 feet per second.

5 feet is the initial height. -16 = half the acceleration (or deceleration due to gravity, 32 feet per second per second)