J.R. S. answered 04/12/21
Ph.D. University Professor with 10+ years Tutoring Experience
This is a typical combustion reaction.
The products will be CO2 and H2O
2C3H7OH + 9O2 ==> 6CO2 + 8H2O
Jade S.
asked 04/12/21J.R. S. answered 04/12/21
Ph.D. University Professor with 10+ years Tutoring Experience
This is a typical combustion reaction.
The products will be CO2 and H2O
2C3H7OH + 9O2 ==> 6CO2 + 8H2O
The reactants here are gaseous oxygen, the kind we breathe, and a hydrocarbon, which can serve as a combustible fuel source. When we burn fuel in an excess of gaseous oxygen, we produce carbon dioxide and water vapor a combustion reaction:
C3H7OH (l) + O2 (g) → CO2 (g) + H2O (g)
This reaction isn't balanced yet, though!
Balance C: C3H7OH (l) + O2 (g) → 3CO2 (g) + H2O (g)
Balance H: C3H7OH (l) + O2 (g) → 3CO2 (g) + 4H2O (g)
Balance O: Uh oh! Since we have 3 on the left and an even number on the right, we'll have to double everything we've done so far.
2C3H7OH (l) + O2 (g) → 6CO2 (g) + 8H2O (g)
We have 2 oxygens from the hydrocarbon and 12 + 8 = 20 oxygens in our products, so we're missing 18 oxygens on the reactants side. We'd fix that with a 9 in front of the gaseous oxygen:
2C3H7OH (l) + 9O2 (g) → 6CO2 (g) + 8H2O (g)
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