Determine ∆G° for the reaction 3 N₂(g) + 2 O₃(g) → 6 NO(g) at 223°C.

Question

DH = +257.7 KJ/mol

DS = +213.7 J/mol K

Answer 1

∆Gº = ∆Hº - T∆Sº

= 257.7kJ - (0.2137 kJ/mol K)(496K)

∆Gº = 151.7 kJ/mol