
Yefim S. answered 04/12/21
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f(x) = x1/3; Δf ≈ df = f'(x)dx = f'(a)(b - a); f'(x) = 1/3 x-2/3; a = 8, b = 10; Δx = 10 - 8 = 2; f'(8) = 1/3(8- 2/3) = 1/12;
So, Δf·≈ 1/12·2 = 1/6; f(10) ≈ f(8) + df = 81/3 + 1/6 = 2 + 1/6 = 2.1667
Error = I101/3 - 2.1667I = I2.1544 - 2.1667I = 0.0123