Calculate ∆S° for C₃H₄(g) + 2 H₂(g) → C₃H₈(g).

Question

C3H4: 266.9 J/mol*K

H2: 130.6 J/mol*K

C3H8: 269.9 J/mol*K

Answer 1

Products - reactants

Products = 269.9 kJ

Reactants = 2 x 130.6 + 266.9 = 528.1 kJ

products - reactants = 269.9 - 528.1 = -258.2 kJ = ∆Sº_rxn