What is S° for B in the reaction 3 A → 2 B if ∆S°(rxn) =-177.8 J/mol ･ K? [S° (A) = (205.0 J/mol ･K)]

Answer 1

3A ==> 2B

Sum or products - sum or reactants = ∆Sreaction

Sum of products = ? = 2x

Sum or reactants = 3 x 205.0 = 615

∆Sreaction = -177.8

-177.8 = 2x - 615

2x = 437.2

x = ∆Sº for B = 218.6 kJ / mol K