What is the entropy when 1.41 moles of CCl₂F₂ vaporize at 25°C? [∆H(vap) = 17.2 kJ/mol at 25°C]

Answer 1

∆S = ∆H / T = 17.2 kJ/mol (298 K)

∆S = 0.0577 kJ/mol K

∆S = 0.0577 kJ/mol K x 1.41 moles = 0.0814 kJ/K = 81.4 J/K

1.41 mol x 17.2 kJ/mol = 24.25 kJ

∆S = 24.25 kJ / 298 K = 0.0814 kJ/K = 81.4 J/K