
Yefim S. answered 04/06/21
Math Tutor with Experience
If we put height from vertex above we get triangle, were one leg is 3cm and altitude of trapezoid is 3√3 cm
Lower base is 10 + 6 = 16 cm
So area a = (10 + 16)3√3/2 = 39√3 cm2.
Alexander S.
asked 04/06/21Yefim S. answered 04/06/21
Math Tutor with Experience
If we put height from vertex above we get triangle, were one leg is 3cm and altitude of trapezoid is 3√3 cm
Lower base is 10 + 6 = 16 cm
So area a = (10 + 16)3√3/2 = 39√3 cm2.
Mark M. answered 04/06/21
Mathematics Teacher - NCLB Highly Qualified
Drop a perpendicular from one corner of the upper base.
A 30-60-90 triangle is formed.
The height (side opposite the 60° angle) is 3√3
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