Find z such that 67% of the standard normal curve lies between −z and z. (Round your answer to two decimal places.)

Answer 1

That would mean that 33% of the area would be outside that interval, evenly divided between both sides, so 16.5% would be above the interval and below the interval. So just need to find z-score associated with bottom 16..5$ or 0.165 probability, which is about -0.97, so because distribution is symmetric, P(-0.97 < z < 0.97) is 67% and z is 0.97.