2 H2O(g) 2 H2(g) + O2(g)

Question

2 H2O(g) 2 H2(g) + O2(g)

If the K is 7.9×10³ at a certain temperature.

At equilibrium, it is found that [H₂] = 6.2×10^-2 M and [O₂] = 2.1×10^-2 M.

The concentration of H₂O at equilibrium is:

......................M

Answer 1

K = [H₂]²[O₂] / [H₂O]²

7.9x10³ = (6.2x10^-2)2(2.1x10^-2) / [H₂O]²

[H₂O] = 1.0x10^-6