2 NOBr(g) 2 NO(g) + Br2(g)

Question

If the constant for is 23.1 of this reaction: 2 NOBr(g) 2 NO(g) + Br2(g) ,

And the concentrations of NO and Br₂ were both 0.784 M

At equilibrium, the concentration of NOBr is?

.........M

Answer 1

If the constant is 23.1...WHAT CONSTANT? Is it the equilibrium constant, K? I'll assume it is.

2NOBr(g) ==> 2NO(g) + Br₂(g)

K = [NO]²[Br₂] / [NOBr]²

23.1 = (0.784)²(0.784) / x

x = 0.0209