How Do you solve how many grams of CE2(SO4)3 would it take to raise the temperature of 50mL

Question

Assuming it would dissolve, how many grams of Ce2(SO4)3 would it take to raise the temperature of 50 mL of water by 10°C? Show your work.

Answer 1

If you know the ∆Hsoln of the salt, you can find the mass of salt needed to raise the temp of 50 ml of water by 10ºC, as follows:

q = mC∆T

q = heat of solution

m = mass of water = 10 ml x 1 g/ml = 10 g

C = specific heat of water = 4.18 J/gº

∆T = change in temperature = 10º

Solving for q we have...

q = (10 g)(4.18 J/gº)(10º) = 418 J

From the ∆Hsoln which is either given to you or you look it up, you can then determine the grams of the salt needed to provide 418 J of heat energy.