J.R. S. answered 04/05/21
Ph.D. University Professor with 10+ years Tutoring Experience
To find the pH, we need to first find the [OH-] from the information provided. Then we can convert this to pOH and then to pH.
Cd(OH)2(s)<==> Cd2+(aq) + 2OH-(aq)
Kd = 7.2x10-15
Let x = [Cd2+] and then [OH-] = 2x
7.2x10-15 = (x)(2x)2 = 4x3
x = 1.8x10-5 M = [Cd2+]
[OH-] = 2 x [Cd2+] = 3.6x10-5 M
pOH = -log [OH-] = 4.44
pH = 14 - pOH
pH = 9.56