How do you find [H30+] and [OH-] of a acid with a molarity of .1M

Question

How do you find [H30+] and [OH-] of a acid with a molarity of .1M

Answer 1

Assuming the acid HA is a strong acid and dissociates completely, the [H3O⁺] = 0.1 M since...

HA ===> H⁺ + A^-

0.1 M.......0.1M...0.1M

[H3O⁺][OH^-] = Kw = 1x10^-14

[OH^-] = 1x10^-14 / 0.1

[OH^-] = 1x10^-13 M