Patrick B. answered 04/05/21
Math and computer tutor/teacher
SAT mean=1109 and stnddev=204
ACT mean=19.5 and stnddev=4.7
Prob(z < Z) = 0.22
then
Z = -0.772193214
by reverse table lookup (Normal.inverse)
The SAT score is -0.772193214 * 204 + 1109 = 951.472584344
The ACT score is -0.772193214 *4.7 + 19.5 = 15.8706918942
For SAT score 1313, the z-score is (1313-1109)/204 = 1
The ACT Score is 1 * 4.7 + 19.5 = 4.7 + 19.5 = 24.2