J.R. S. answered 04/02/21
Ph.D. University Professor with 10+ years Tutoring Experience
Common Ion Effect:
AgIO3(s) <==> Ag+(aq) + IO3-(aq) ... Ksp = 3.0x10-8
Ksp = 3.0x10-8 = [Ag+][IO3-] = (x)(0.125)
x = 2.4x10-7 M = solubility of AgIO3 in 0.125 M NaIO3
La(IO3)3(s) <==> La3+(aq) + 3IO3-(aq) ... Ksp = 7.5x10-12
Ksp = 7.5x10-12 = [La3+][IO3-]3 = (x)(0.125)3
x = 3.8x10-9 M = solubility of La(IO3)3 in 0.125 M NaIO3