calculating the pressure, volume, and/or temperature using the following gas laws: Charles’ Law, Boyle’s Law, and Gay-Lussacs Law

Question

Suppose 336.0 mL of oxygen is collected at 25℃. What will the volume be if the temperature is increased to 50.0℃?

Answer 1

V1 = 336.0 ml

T1 = 25ºC + 273 = 298K

V2 = ?

T2 = 50.0ºC + 273 = 323K

The pressure is assumed to be constant since it isn't mentioned. This then would involve Charles' Law:

V1/T1 = V2/T2 and solving for V2, we have..

V2 = V1T2/T1 = (336 ml)(323K) / 298K

V2 = 364 ml