For the reaction below, Kc = 1.10 × 10⁻⁴. What is the equilibrium concentration of C if the reaction begins with 0.200 M A and 0.150 M B? 2 A (aq) + B (aq) ⇌ C (aq)

Answer 1

Use an ICE table.

2A(aq) + B(aq) <==> C(aq)

0.200.....0.150...........0........Initial

-2x.........-x................+x.......Change

0.2-2x....0.15-x..........x........Equilbrium

K = 1.10x10^-4 = [C] / [A]²[B]

1.1x10^-4 = x / (0.2-2x)²(0.15-x)

To solve for the equilibrium concentration of C, simply solve for x and that will be the answer. This now becomes a math/algebra problem, which hopefully you can solve.