For the reaction: 2 A (g) + B (s) ⇌ 2 C (s) + D (g) At 298 K in a 10.0 L vessel, the equilibrium values are as follows: 0.721 atm of A, 4.18 mol of B, 6.25 mol of C, and 8.75 atm of D.

Question

What is the value of the equilibrium constant?

Answer 1

2A(g) + B(s) <==> 2C(s) + D(g)

Keq = (D) / (A)² (note: solids are NOT included in the equilibrium expression)

Keq = 8.75 / (0.721)²

Keq = 16.8