J.R. S. answered 04/01/21
Ph.D. University Professor with 10+ years Tutoring Experience
No additional data is needed.
moles NaOH needed for neutralization = 40 ml x 1L/1000 ml x 0.005 mol/L = 0.0002 moles NaOH
moles H2SO4 present = 0.0002 mol NaOH x 1 mol H2SO4 / 2 mol NaOH = 0.0001 moles H2SO4 present
Concentration of H2SO4 = 0.0001 moles/0.01 L = 0.01 M