Determine K for a reaction at 200 K if ∆G° =24.0 kJ/mol. (R = 8.314 J/mol ･ K)

Answer 1

∆G = ∆Gº + RT ln K

At equilibrium, ∆G = 0 and ...

∆Gº = -RT ln K

24.0 kJ/mol = -(0.008314 kJ/Kmol)(200K) ln K

ln K = 24.0 / -1.66 = -14.5

K = 5x10^-7