John L. answered 03/31/21
Naval Academy graduate with more than 10 years experience in teaching
The series is geometric with r<1 or convergent. The trick is to identify the A/R in the series.
Recalling exponential laws:
5/2^*n-1) = 5/2^n * 5/2^-1 = 10/2^n or expanded 10(1 + .5 +.5^2 +.5^3..etc) So A = 10, R = 1/2 and then Sum = a/(1-r) or 20.