Geometry trigonometry

Question

In ABCD the measure of D=90 the measure of B=22 and DB=44 feet find the length of BC to the nearest tenth of a foot

Answer 1

cos22° = 44/x

So, x = 44 / cos22° ≈ 47.555

Answer 2

This triangle needs to be labeled correctly.

α=22°

β=?

γ=90°

a=44

b=?

c=?

β=180-90-22=68°

a/sinα=b/sinβ=c (sin of a rt <=1)

44/.374=117.45=c

a^2+b^2=c^2

1936+b^2=13796

11860^.5=108.9=b