Per the Pythagorean Theorem:
(x)^2 + (2x - 1)^2 = (2x + 1)^2
x^2 + 4x^2 - 4x + 1 = 4x^2 + 4x + 1
x^2 - 4x + 1 = 4x + 1
x^2 - 8x = 0
x(x-8) = 0
x = 8
2x - 1 = 15
2x + 1 = 17
Alyssa Z.
asked 03/30/21A right triangle has legs of lengths x and 2x − 1 and a hypotenuse of length
2x + 1. What are the lengths of its sides? (Enter your answers from smallest to largest.)
Per the Pythagorean Theorem:
(x)^2 + (2x - 1)^2 = (2x + 1)^2
x^2 + 4x^2 - 4x + 1 = 4x^2 + 4x + 1
x^2 - 4x + 1 = 4x + 1
x^2 - 8x = 0
x(x-8) = 0
x = 8
2x - 1 = 15
2x + 1 = 17
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