
Mark M. answered 03/29/21
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
2 sin2 θ = sin θ
2 sin2 θ - sin θ = 0
sin θ (2 sin θ - 1) = 0
Can you solve for θ and answer?
Jesus C.
asked 03/29/212 sin^2 theta = sin theta
Mark M. answered 03/29/21
Mathematics Teacher - NCLB Highly Qualified
2 sin2 θ = sin θ
2 sin2 θ - sin θ = 0
sin θ (2 sin θ - 1) = 0
Can you solve for θ and answer?
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