Transform x to N(0,1) via z-score
z = (x - mean)/SD, where x = 42, mean = 54 and SD = 8
z = (42 - 54)/8 = -1.5
P(x < 42) = P(z < -1.5).
That probability can be found from standard normal probability distribution table
Kay C.
asked 03/29/21Transform x to N(0,1) via z-score
z = (x - mean)/SD, where x = 42, mean = 54 and SD = 8
z = (42 - 54)/8 = -1.5
P(x < 42) = P(z < -1.5).
That probability can be found from standard normal probability distribution table
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