Please Read the Description

Question

Cyclopentadiene (C₅H₆) reacts with itself to form dicyclopentadiene (C₁₀H₁₂). A 0.880 M solution of C₅H₆ is monitored as a function of time as the reaction proceeds. A graph of In[C₅H₆] versus time yields a straight line.

How many seconds will it take for the [C₅H₆] to be 0.110 M? The k for the reaction is 0.209s^-1.

___ s

If someone could help me, It would be greatly appreciated.

Answer 1

Since a graph of ln[C₅H₆] is linear, this tell us the reaction is first order in C5H6. This is the first thing we need to determine. Now that we know it is first order, we can use the appropriate equations to find the answer to the question.

The equation used to generate the straight line was ln[C5H6] = -kt + ln [A]_o

Plugging in our values and solving for t, we have...

ln (0.110 M) = -0.209/s (t) + ln 0.880 M

-2.21 = -0.209 t + (-0.128)

-2.08 = -0.209 t

t = 9.96 seconds

(be sure to check the math)