The integral is -1/(2 (ln(k))^2) + C; -1/(2 ln^2(k)) has a limit of 0 as x goes to infinity. Note the negative sign; this assures us that the integral will be positive.
Thus, the sum converges.
Cameron L.
asked 03/27/21Use the integral test to determine if the series
is convergent or divergent. Make sure that you set up the problem correctly and use the proper notation.
The integral is -1/(2 (ln(k))^2) + C; -1/(2 ln^2(k)) has a limit of 0 as x goes to infinity. Note the negative sign; this assures us that the integral will be positive.
Thus, the sum converges.
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