The sum of the measures of the angles of a pentagon is (5-2)180 = 540
sum of arithmetic sequence
n(2a+ (n-1)d)/2
so given a is 60, n = 5, find d:
540 = 5(120+4d)/2
1080 = 600 + 20d
480 = 20d
d = 24
so sides are:
60, 84, 108, 132, 156
Ryan B.
asked 03/27/21Find the measures of each angle of a pentagon where the measures of the angles form an arithmetic sequence and the smallest measure is 60 deg.
The sum of the measures of the angles of a pentagon is (5-2)180 = 540
sum of arithmetic sequence
n(2a+ (n-1)d)/2
so given a is 60, n = 5, find d:
540 = 5(120+4d)/2
1080 = 600 + 20d
480 = 20d
d = 24
so sides are:
60, 84, 108, 132, 156
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