What is the entropy when 1.38 moles of CCl₂F₂ vaporize at 25°C? [∆H(vap) = 17.2 kJ/mol at 25°C]

Answer 1

You are given the ∆Hvap as 17.2 kJ/mol and you are told that you are vaporizing 1.38 moles, so how many kJ do you think it will take?

If you had 2 moles, it would take 2 x 17.2 kJ, right? If you had 10 moles, it would take 10 x 17.2 kJ, right?

So, you should be able to figure out if you have 1.38 moles, how many kJ it will take. Right?