Use Ka * Kb = Kw to first solve for Ka. Then use ICE to calculate [H+] (ignore the H+ from water, too small to matter) and then calculate -log [H+]
Ray A.
asked • 03/26/21What is the pH of 0.75M solution of C5H5 NHCl? Kb for C5H5N = 1.7*10^ -9
What is the pH of 0.75M solution of C5H5 NHCl? Kb for C5H5N = 1.7*10^ -9
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