Calculate ∆S° for NH₃(g) + HCl(g) → NH₄Cl(s).

Question

NH3 192.5 J/mol.k

HCI 186.7 J/mol.k

NH4CI 94.6 J/mol.k

Answer 1

∑Products - ∑Reactants

∑products = 94.6 J/mol-K

∑reactants = 192.5 J/mol-K + 186.7 J/mol-K = 379.2 J/mol-K

∆Sº = 94.6 - 379.2 = -284.6 J/mol-K