What is S° for B in the reaction 3 A → 2 B if ∆S°(rxn) =-199.8 J/mol ・ K? [S° (A) = (205.0 J/mol ・K)]
3A ==> 2B
∆Sºrxn = 2xSº B - 3xSº A
-199.8 = 2SºB - 3*205
-199.8 = 2SºB - 615
Sº (B) = 207.6 J/molK
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