(1 - 0.5688)/2 = 0.2156 area on either side of interval
Look for z value that corresponds to lower 0.2156. That z is -0.787, so b = 0.787.
Lexi O.
asked 03/25/21Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1.If P(−b<z<b)=0.5688, find b.
b=
(1 - 0.5688)/2 = 0.2156 area on either side of interval
Look for z value that corresponds to lower 0.2156. That z is -0.787, so b = 0.787.
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