Robert S. answered 03/25/21
PhD in Chemistry with industrial R&D and teaching experience
Hello, Holly,
I answered a similar problem for you and am wondering if you could explain which part of the process is proving the most difficult. Also, it would be nice to post as far as you got. Having the molar masses already calculated for the key compounds would not only help save time for those answering, but would also demonstrate what portions of the problem don't need explaining. Thanks.
Part 1: The balanced equation promises us one mole of nitrogen for every 3 moles of CuO. Bummer, but we know the molar ratio is (1/3) N2/CuO. Since we start with 11.8 moles of CuO, we'll get 11.8*(1/3) moles of N2. That's 3.93 moles N2. Multiply by the molar mass of N2 to find grams (110 grams).
Part 2. The molar ratio of H2 to CH4 is 2. We need twice as many moles of hydrogen to produce a mole of CH4. We have 14.9 moles of methane, so we'll need 2*14.9 = 29.8 moles of H2. At 2 g/mole, that is 59.6 grams.
Bob