CI = mean +/ margin of error = 1.32 +/- 0.04 = (1.28,1.32).
Esther D.
asked • 03/24/21Find the confidence interval.
In a simple random sample of n households, the sample mean number of personal computers was 1.32. Assume the population standard deviation is 0.41. Margin of error is computed to be 0.04.
Find the confidence interval.
The confidence interval to contain the population mean number of personal computers is between ______ and _______.
Follow
•
1
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
