What is the equation of the line that is perpendicular to the linear graph of y= -2/3x +5 and passes through the point (0, –2)?

Question

What is the equation of the line that is perpendicular to the linear graph of  and passes through the point (0, –2)?

Answer 1

slope of a perpendicular line is the negative inverse. Negative inverse of -2/3 is 3/2. Just change the sign and flip the fraction upside down.

y =3x/2 + b, solve for b by plugging in the point (0,-2) or notice that is the y intercept of -2

y = 3x/2 -2 is the perpendicular line through the given point