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Question

A jar contains 6 red marbles numbered 1 to 6 and 8 blue marbles numbered 1 to 8. A marble is drawn at random from the jar. Find the probability the marble is red or odd-numbered.

Answer 1

P(R) = 6/14 = 3/7

P(O) = (3+4)/14 = 1/2

P(R&O) =3/14 (3 of the red marbles are odd)

P(RvO) = P(R) + P(O) - P(R&O) = 3/7 + 1/2 - 3/14 = (6+7-3)/14 = 10/14 = 5/7

Probability of selecting randomly and getting a red that is odd = 5/7 = about 71.4%

Of the 14 marbles, 6 are red and of the 8 non-red 4 are odd. 6+4=10 10/14 = 5/7