Raymond B. answered 03/23/21
Math, microeconomics or criminal justice
f'(x) = the derivative of 2^x = ln2(2^x)
f'(0) = ln2(2^0) = ln2 = slope of the tangent line at the point (0,1)
y= xln2 + b is the equation of the tangent line. solve for b by plugging in the point (0,1)
1 = 0 + b
b = 1
y = xln2 + 1 is the tangent line to the curve at the given point
Lily P.
Thank u so much!03/23/21