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Question

Acetylene C2H2 gas and oxygen O2 gas react to form carbon dioxide CO2 gas and water H2O vapor. Suppose you have 11.0 mol of C2H2 and 2.0 mol of O2 in a reactor. Calculate the largest amount of CO2 that could be produced. Round your answer to the nearest 0.1 mol.

Answer 1

First, you need a correctly balanced equation:

2C₂H₂ + 5O₂ ==> 4CO₂ + 2H₂O ... balanced equation

Next, find the limiting reactant, if any. One easy way to do this is to divide the moles of each reactant by its coefficient in the balanced equation.

For C₂H₂ we have 11.0 mol / 2 = 5.5

For O₂ we have 2.0 mol / 5 = 0.4 SO O₂ IS LIMITING

Now, use the moles of limiting reactant to find theoretical yield of CO2:

2.0 mol O₂ x 4 moles CO₂ / 5 mol O₂ = 1.6 moles CO₂