J.R. S. answered 03/22/21
Ph.D. University Professor with 10+ years Tutoring Experience
For the first problem, you can use the formula V1M1 = V2M2
V1 = initial volume
M1 = initial molarity
V2 = final volume
M2 = final molarity
1). (30.0 ml)(3.8 M) = (650.0 ml)(x M)
x = 0.18 M (2 sig. figs.)
2). For this problem, we need to find moles of NaCl in each solutions, find the total final volume, and calculate molarity from these values.
229 ml x 1 L/1000 ml x 0.720 mol/L = 0.16488 moles NaCl
572 ml x 1 L/1000 ml x 0.420 mol/L = 0.2402 moles NaCl
Total moles NaCl = 0.4051 moles
Total volume = 0.229 L + 0.572 L = 0.801 L
Final NaCl concentration = 0.4051 moles NaCl / 0.801 L = 0.506 M (3 sig. figs.)