This is a classic hypergeometric distribution question and you should be able to write the answer down directly as
9C6 * 6C4 / 15C10 where the C's are the binomial coefficients.
The first is the number of ways of picking 6 boys from the 9 available, the second is the number of ways of picking 4 other (presumably girls) from the other 6 students.
The numerator is the answer to the problem. The denominator is the number of ways of picking 10 from a group of 15 and the quotient is the probability of picking 9 boys and 6 girls for the team.