P(-1.8 < z < 0.2) = P(z < 0.2) - P(z < -1.80) = 0.5793 - 0.0359 = 0.5434
Jocelyn A.
asked • 03/20/21probability for a normal distribution
P(-1.80<z<.20)=.
.4207-.0359=.3848
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Jocelyn A.
Thank you03/21/21